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The Zero Factor Betting System

Zero Factor Betting System

Betting “all sides”; is that really The Most Stupid Bet?

Mr. Oops explains why this seemingly stupid bet can be a really good idea…

DO YOU use progressions? Do you bet on the “even” chances, Columns, Dozens, or the Streets (3- or 6-numbers)? If your answer is “yes” to both questions, this one is for you! I am going to show you that betting “all sides” of a bet – meaning both Red AND Black, all three Dozens or, why not, all twelve Single Streets at the same time – will eliminate a part of the loss when a Zero hits and, in the case of the “even” chances, will need a smaller bankroll than needed when betting one side only!

Why the latter is the case, is explained in Part 2, while showing how to achieve the former will be done with the aid of an example sequence of spins (25 – 10 – 18 – 25 – 33 – 7 – 30 – 7 – 0 – 29) where a progression (Martingale) is used on the Low/High bet. I chose the Low/High bet because of simplicity (you can easily see which won) and the Martingale because of clarity (a double bet is very distinct). However, all of this is adaptable to other progressions and all the above-mentioned bets, and you will have no problems understanding how to use your favorites.

To really understand what happens here, I think it is necessary to first show what happens if only one side at the time is bet. Let us start with Low:

Spin 1: We bet 1 on Low. Decision: 25 High. We lose. Net Result: -1
Spin 2: We bet 2 on Low. Decision: 10 Low. We win. Acc Net Result: +1
Spin 3: We bet 1 on Low. Decision: 18 Low. We win. Acc Net Result: +2
Spin 4: We bet 1 on Low. Decision: 25 High. We lose. Acc Net Result: +1
Spin 5: We bet 2 on Low. Decision: 33 High. We lose. Acc Net Result: -1
Spin 6: We bet 4 on Low. Decision: 7 Low. We win. Acc Net Result: +3
Spin 7: We bet 1 on Low. Decision: 30 High. We lose. Acc Net Result: +2
Spin 8: We bet 2 on Low. Decision: 7 Low. We win. Acc Net Result: +4
Spin 9: We bet 1 on Low. Decision: ZERO! We lose. Acc Net Result: +3
Spin 10: We bet 2 on Low. Decision: 29 High. We lose. Acc Net Result: +1

The Zero Factor Part 2

SpinLow/HighBetDecisionWin/LoseAcc Net Result
11 Low + 1 HighWe bet Nothing as the two are equal5 Low0
21 Low + 2 High We bet 1 on High as 2 – 1 = 16 LowLose-1
31 Low + 4 High We bet 3 on High as 4 – 1 = 310 LowLose-4

 
As we lost the 4 units on High, we terminate the session.

As you can see, the bankroll needed is not 7 units; it’s only 4! But this is the Martingale; I have used it in the examples because it is a simple progression and it clearly shows what is happening. As I have said before; any progression can be used. When using the Martingale progression, we mostly have the lowest bet of 1 unit, meaning that the other bets are not lowered very much. There can be a big difference, however, if you use a progression that does not immediately return to the lowest bet after a win (and/or you start with another value than 1). Such a progression is the d’Alembert; increase your bet by 1 unit after a loss and decrease it by 1 unit after a win. Let’s see what would have happened if we had used this progression instead, betting the ten spins from Part 1.

SpinLow/HighBetDecisionWin/LoseAcc Net Result
11 Low + 1 HighWe bet Nothing as the two are equal25 High0
22 Low + 1 HighWe bet 1 on Low as 2 – 1 = 110 LowWin+1
31 Low + 2 HighWe bet 1 on High as 2 – 1 = 118 LowLose0
41 Low + 3 HighWe bet 2 on High as 3 – 1 = 225 HighWin+2
52 Low + 2 HighWe bet Nothing as the two are equal33 High+2
63 Low + 1 HighWe bet 2 on Low as 3 – 1 = 27 LowWin+4
72 Low + 2 High We bet Nothing as the two are equal30 High+4
83 Low + 1 HighWe bet 2 on Low as 3 – 1 = 27 LowWin+6
92 Low + 2 HighWe bet Nothing as the two are equalZERO!+6
103 Low + 3 HighWe bet Nothing as the two are equal29 High+6

 

Compare this result with the two results from betting one side at the time or the added result of both – these figures:

Low/HighBet TotalWon TotalNet Total
Low20 Units18 Units-2 Units
High18 Units22 Units+4 Units
Low/High Added38 Units40 Units+2 Units
Low/High Difference8 Units14 Units+6 Units

 
This is FOUR UNITS MORE – the bet we didn’t do when the Zero hit (Spin 9)! Also note that only a total of EIGHT units were at stake, instead of 38 – not even one-quarter of the added bets!

Suppose now, that we have four Low hits in a row:

SpinLow/HighBetDecisionWin/LoseACC Net Result
Spin 114 Low + 2 HighWe bet 2 on Low as 4 – 2 = 216 LowWin+8
Spin 123 Low + 3 HighWe bet Nothing as the two are equal18 Low+8
Spin 132 Low + 4 HighWe bet 2 on High as 4 – 2 = 217 LowLose+6
Spin 141 Low + 5 HighWe bet 4 on High as 5 – 1 = 415 LowLose+2

 
Now, the figures are:
 

Low/HighBet TotalWon TotalNet Total
Low30 Units38 Units+8 Units
High32 Units22 Units-10 Units

 

Low/HighBet TotalWon TotalNet Total
Low/high Added62 Units60 Units-2 Units
Low/High Difference16 Units18 Units+2 Units

 
By using only 16 units instead of 62 – close to 25% – we have turned a negative result into a positive one! There is still only the four units difference (due to the Zero at Spin 9) but in this case that is enough to keep us on the safe side. For a while…

As a final, let me show you the Reversed Labouchere applied to the different betting on the 14 spins above. I will use the line (also bankroll) “1 – 2 – 3 – 4” (first bet is 5 units, total bankroll is 10), adding won bets (to the right) and canceling lost ones. The minimum bet is 5 units. This one is going to LOSE! Here we go:

L line: 1 – 2 – 3 – 4
H line: 1 – 2 – 3 – 4
Spin 1: (5 Low + 5 High) We bet Nothing as the two are equal. Decision: 25 High. Net Result: 0

L line: X – 2 – 3 – X
H line: 1 – 2 – 3 – 4 – 5
Spin 2: (5 Low + 6 High) We bet 1 on High as 6 – 5 = 1. Decision: 10 Low. We lose. Acc Net Result: -1

L line: X – 2 – 3 – X – 5
H line: X – 2 – 3 – 4 – X
Spin 3: (7 Low + 6 High) We bet 1 on Low as 7 – 6 = 1. Decision: 18 Low. We win. Acc Net Result: 0

L line: X – 2 – 3 – X – 5 – 7
H line: X – X – 3 – X – X ==> Next bet less than min. Bankroll #1 gone (-7) NEW LINE! 1 – 2 – 3 – 4
Spin 4: (9 Low + 5 High) We bet 4 on Low as 9 – 5 = 4. Decision: 25 High. We lose. Acc Net Result: -4

L line: X – X – 3 – X – 5 – X
H line: 1 – 2 – 3 – 4 – 5
Spin 5: (8 Low + 6 High) We bet 2 on Low as 8 – 6 = 2. Decision: 33 High. We lose. Acc Net Result: -6

L line: X – X – X – X – X – X ==> Bankroll #2 gone (-10, Tot -17) NEW LINE! 1 – 2 – 3 – 4
H line: 1 – 2 – 3 – 4 – 5 – 6
Spin 6: (5 Low + 7 High) We bet 2 on High as 7 – 5 = 2. Decision: 7 Low. We lose. Acc Net Result: -8

L line: 1 – 2 – 3 – 4 – 5
H line: X – 2 – 3 – 4 – 5 – X
Spin 7: (6 Low + 7 High) We bet 1 on High as 7 – 6 = 1. Decision: 30 High. We win. Acc Net Result: -7

L line: X – 2 – 3 – 4 – X
H line: X – 2 – 3 – 4 – 5 – X – 7
Spin 8: (6 Low + 9 High) We bet 3 on High as 9 – 6 = 3. Decision: 7 Low. We lose. Acc Net Result: -10

L line: X – 2 – 3 – 4 – X – 6
H line: X – X – 3 – 4 – 5 – X – X
Spin 9: (8 Low + 8 High) We bet Nothing as the two are equal. Decision: ZERO! Acc Net Result: -10

L line: X – X – 3 – 4 – X – X
H line: X – X – X – 4 – X – X – X Bankroll #3 gone (-6, Tot -23) NEW LINE! 1 – 2 – 3 – 4
Spin 10: (7 Low + 5 High) We bet 2 on Low as 7 – 5 = 2. Decision: 29 High. We lose. Acc Net Result: -12

L line: X – X – X – X – X – X Bankroll #4 gone (-10, Tot -33) NEW LINE! 1 – 2 – 3 – 4
H line: 1 – 2 – 3 – 4 – 5
Spin 11: (5 Low + 6 High) We bet 1 on High as 6 – 5 = 1. Decision: 16 Low. We lose. Acc Net Result: -13

L line: 1 – 2 – 3 – 4 – 5
H line: X – 2 – 3 – 4 – X
Spin 12: (6 Low + 6 High) We bet Nothing as the two are equal. Decision: 18 Low. Acc Net Result: -13

L line: 1 – 2 – 3 – 4 – 5 – 6
H line: X – X – 3 – X – X Bankroll #5 gone (-7, Tot -40) NEW LINE! 1 – 2 – 3 – 4
Spin 13: (7 Low + 5 High) We bet 2 on Low as 7 – 5 = 2. Decision: 17 Low. We win. Acc Net Result: -11

L line: 1 – 2 – 3 – 4 – 5 – 6 – 7
H line: X – 2 – 3 – X
Spin 14: (8 Low + 5 High) We bet 3 on Low as 8 – 5 = 3. Decision: 15 Low. We win. Acc Net Result: -8

At the end of this series of 14 spins, we could have (if we had bet the added bets) been betting a whopping 178 units (Low 92, High 86) and won a total of 154 units (Low 98, High 56) giving a total net result of -24. We also had to be prepared to use at least seven bankrolls (5 lost and two in working), meaning a total of at least 70 units. Betting the difference, we had a TOTAL of 22 units AT STAKE – that’s less than the TOTAL RESULT for betting the added – and won 14 giving us a net result of -8. In terms of bankrolls/lines we never used two as the worst down was 13 units and in terms of betting only one side, we can divide the added result by two to get a figure in between Bet 89 units, Won 77 units, Lost 2.5 lines or bankrolls and having a total of 6.5 units in profit, working. So at least 4 bankrolls were needed here, meaning a total of 40 units as we lost 2.5 x 10 units and have one line in working. The “difference betting” did never even get close to two.

In my opinion, this is saving money!

Zero Factor Bankroll Benefit Part 3

The most obvious benefit is that you need one bankroll LESS than you would, had you bet the sum of all bets. So for betting Red/Black, you will only need one bankroll, for betting all the Dozens you need two, for the Double Streets five, and for the Single Streets, you will need eleven bankrolls. Let me explain why this is so:

The technique behind betting the difference is, as we saw in Part 1, to subtract the lowest bet from all bets. One consequence of this is that the lowest bet will reduce itself to nothing and this will happen every time you are betting. And then, as you actually completely delete one bet every time, you are saving one bankroll namely the bankroll handling the “lowest bet”.

But you don’t have a bankroll handling the lowest bets, only the Red/Black bankroll! Well, that doesn’t matter, really; as you are deleting one bet every spin, no matter what bet – this will even out in the long run – you are in fact deleting one complete bankroll, and deleting one bankroll means that one bankroll is saved. That’s why you only need

For betting RED and BLACK: 1 bankroll
For betting LOW and HIGH: 1 bankroll
For betting EVEN and ODD: 1 bankroll
For betting ALL COLUMNS: 2 bankrolls
For betting ALL DOZENS: 2 bankrolls
For betting ALL DOUBLE STREETS: 5 bankrolls
For betting ALL SINGLE STREETS: 11 bankrolls

But this is not all
: You will, in reality, need even less than that! This is due to the fact that you always subtract the lowest bet from all bets thus diminishing all bets to some degree – admittedly most of the time by one single unit only. But this is enough to give you a reduction of your bankroll needs and this is especially obvious for the “even” chances Red/Black, Low/High, or Even/Odd as the bankroll needed for betting both ways at the same time is LESS than what is needed for betting only one side! First, you delete one bet/bankroll so you will only need one. But then your lowest bet (that never will be actually bet) will reduce the other bet thus giving the result of a lower bet than what should have been bet in an original way.

Let’s look at it this way: We are going to bet the Martingale up to, and including the third bet, thus the bankroll needed is 1 + 2 + 4 = 7 units (this is NOT a recommended way to play). If the third bet (4 units) is lost, we stop the game. Now, we hit the bad streak:

The Zero Factor Part 4

Spin 10: 1 + 5 = 6. (This is true for all spins – check it!)
So, what’s the benefit here? The answer is: There is none! There is no benefit at all, because of the way we made the bets; we were betting as if we were two persons betting one side each, and at the end of the series we put our results together. This is obviously a dead-end but we can do exactly the same thing in a much better way: Betting the DIFFERENCE between the two bets (or between ALL bets, if you are betting something else). This means that you subtract the lowest bet (in units) from all bets – even itself, thereby making itself a zero-unit bet (no bet). Have a look at the same sequence as above, bet this way:

SpinLow/HighBetDecisionWin/LoseAcc Net Result
11 Low + 1 HighWe bet Nothing as the two are equal25 High0
22 Low + 1 High We bet 1 on Low as 2 – 1 = 110 LowWin+1
31 Low + 2 High We bet 1 on High as 2 – 1 = 118 LowLose0
41 Low + 4 HighWe bet 3 on High as 4 – 1 = 325 HighWin+3
52 Low + 1 HighWe bet 1 on Low as 2 – 1 = 133 HighLose+2
64 Low + 1 HighWe bet 3 on Low as 4 – 1 = 37 LowWin+5
71 Low + 2 HighWe bet 1 on High as 2 – 1 = 130 HighWin+6
82 Low + 1 HighWe bet 1 on High as 2 – 1 = 17 LowWin+7
91 Low + 2 HighWe bet 1 on High as 2 – 1 = 1ZERO!Lose+6
102 Low + 4 HighWe bet 2 on High as 4 – 2 = 229 HighWin+8

 

As we saw above, when we actually bet both sides at the same time, the result after spin 8 was +7 units. This last way, the result is the same – exactly as all the other results before the eighth spin (check it). So there is still no benefit up to and including Spin 8! The truth is:

As long as the Zero doesn’t hit, the result of betting the difference will always be exactly the same as betting all sides at the same time. But when the Zero hits, only the difference is at stake thus losing less than if both sides had been bet – this is “The Zero Factor”.

Now compare the “added” result with the “difference” result after the 9th spin, when the Zero has hit: Betting both sides, the result is +4 but betting the difference keeps our result up at +6 – that’s two units more! And this difference will be the same for all future spins (as can be seen at Spin 10 where the “added” result is +6 while the “difference” result is +8) until the zero hits again when the difference will be even bigger.

As the last example in this part, I will show you how to calculate the “difference” bets when you are betting, for example, the Double Streets (6 numbers). Suppose your six bets – according to your six separate progressions – are 5 + 6 + 2 + 6 + 2 + 3 for Streets 1 to 6 respectively. The lowest bet is 2 and in this figure, we subtract from all bets including the 2s themselves. This ends up in that for Streets 1 to 6 you shall bet 3 + 4 + 0 + 4 + 0 + 1 (no bets on Streets 3 and 5). Whichever street wins, your result will be exactly the same in both cases (try it!) but if the Zero hits you will lose only 12 units betting the difference, compared to betting all streets when the loss would be 24 – you save HALF the bet!

This is saving money exploiting “The Zero Factor

In the second part, I will show you why a smaller bankroll is needed when betting both sides of “even” chances, compared to betting one side only. There is, however, something there even for you who bet the thirds or the streets as the savings are considered using the “difference” instead of all sides – you always save more than one bankroll!

IN PART 1 we learned that any kind of progression and any of the bets “Even”, Thirds or Streets, will benefit from betting the difference of an all-sides betting. But this way may at first appear expensive as you have to bet all sides – two bankrolls for Red/Black betting, three for Dozens, etc. Please, let me assure you this is not so.

The Zero Factor Part 5

Spin 8: +4,

Spin 9: +3 and

Spin 10: +1 as those figures are keys to understanding how this works. Now let’s see what happens when we are betting High:

SpinBetDecisionWin/LoseAcc Net Result
11 on High25 HighWin+1
21 on High10 LowLose0
32 on High18 LowLose-2
44 on High25 HighWin+2
51 on High33 HighWin+3
61 on High7 LowLose+2
72 on High30 HighWin+4
81 on High7 LowLose+3
92 on HighZERO!Lose+1
104 on High29 HighWin+5

 

(Please note the three last results) This is not a bad ending, is it? We are 1 unit up on Low and 5 units up on High despite we had a total loss on the Zero. So it didn’t matter which side we were betting on; the end result is positive. But what would happen if we bet BOTH sides at the SAME TIME?

SpinBetTotal BetDecisionWin/LoseAcc Net Result
11 Low + 1 High225 HighWin 1, Lose 10
22 Low + 1 High310 LowWin 2, Lose 1+1
31 Low + 2 High318 LowWin 1, Lose 20
41 Low + 4 High525 HighWin 4, Lose 1+3
52 Low + 1 High333 HighWin 1, Lose 2+2
64 Low + 1 High57 LowWin 4, Lose 1+5
71 Low + 2 High330 HighWin 2, Lose 1+6
82 Low + 1 High37 LowWin 2, Lose 1+7
91 Low + 2 High3ZERO!Win 0, Lose 3+4
102 Low + 4 High629 HighWin 4, Lose 2+6

 

If you compare these last three results with the sum of the same results above, you will find that they are exactly the same:

Spin 8: 4 + 3 = 7,

Spin 9: 3 + 1 = 4

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